Ordinary Differential Equations/Successive Approximations

has a solution satisfying the initial condition , then it must satisfy the following integral equation:

Now we will solve this equation by the method of successive approximations.

Define as:

And define as

We will now prove that:

  1. If is bounded and the Lipschitz condition is satisfied, then the sequence of functions converges to a continuous function
  2. This function satisfies the differential equation
  3. This is the unique solution to this differential equation with the given initial condition.

Proof

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First, we prove that   lies in the box, meaning that  . We prove this by induction. First, it is obvious that  . Now suppose that  . Then   so that

 . This proves the case when  , and the case when   is proven similarily.

We will now prove by induction that  . First, it is obvious that  . Now suppose that it is true up to n-1. Then

  due to the Lipschitz condition.

Now,

 .

Therefore, the series of series   is absolutely and uniformly convergent for   because it is less than the exponential function.

Therefore, the limit function   exists and is a continuous function for  .

Now we will prove that this limit function satisfies the differential equation.