Ordinary Differential Equations/Successive Approximations

has a solution satisfying the initial condition , then it must satisfy the following integral equation:

Now we will solve this equation by the method of successive approximations.

Define as:

And define as

We will now prove that:

  1. If is bounded and the Lipschitz condition is satisfied, then the sequence of functions converges to a continuous function
  2. This function satisfies the differential equation
  3. This is the unique solution to this differential equation with the given initial condition.


First, we prove that   lies in the box, meaning that  . We prove this by induction. First, it is obvious that  . Now suppose that  . Then   so that

 . This proves the case when  , and the case when   is proven similarily.

We will now prove by induction that  . First, it is obvious that  . Now suppose that it is true up to n-1. Then

  due to the Lipschitz condition.



Therefore, the series of series   is absolutely and uniformly convergent for   because it is less than the exponential function.

Therefore, the limit function   exists and is a continuous function for  .

Now we will prove that this limit function satisfies the differential equation.