Yet Another Haskell Tutorial/Type advanced
As you've probably ascertained by this point, the type system is integral to Haskell. While this chapter is called "Advanced Types", you will probably find it to be more general than that and it must not be skipped simply because you're not interested in the type system.
Type Synonyms
editType synonyms exist in Haskell simply for convenience: their removal would not make Haskell any less powerful.
Consider the case when you are constantly dealing with lists of
three-dimensional points. For instance, you might have a function
with type [(Double,Double,Double)] -> Double ->
[(Double,Double,Double)]
. Since you are a good software engineer,
you want to place type signatures on all your top-level functions.
However, typing [(Double,Double,Double)]
all the time gets very
tedious. To get around this, you can define a type synonym:
type List3D = [(Double,Double,Double)]
Now, the type signature for your functions may be written List3D ->
Double -> List3D
.
We should note that type synonyms cannot be self-referential. That is, you cannot have:
type BadType = Int -> BadType
This is because this is an "infinite type." Since Haskell removes
type synonyms very early on, any instance of BadType
will be
replaced by Int -> BadType
, which will result in an infinite loop.
To make a recursive type, one would use newtype
newtype GoodType = MakeGoodType (Int -> GoodType)
Type synonyms can also be parameterized. For instance, you might want
to be able to change the types of the points in the list of 3D
points. For this, you could define:
type List3D a = [(a,a,a)]
Then your references to [(Double,Double,Double)]
would become
List3D Double
.
Newtypes
editConsider the problem in which you need to have a type which is very
much like Int
, but its ordering is defined differently. Perhaps
you wish to order Int
s first by even numbers then by odd numbers
(that is, all odd numbers are greater than any even number and within
the odd/even subsets, ordering is standard).
Unfortunately, you cannot define a new instance of Ord
for
Int
because then Haskell won't know which one to use. What you
want is to define a type which is isomorphic to Int
.
Note
"Isomorphic" is a common term in mathematics which basically means "structurally identical." For instance, in graph theory, if you have two graphs which are identical except they have different labels on the nodes, they are isomorphic. In our context, two types are isomorphic if they have the same underlying structure.
One way to do this would be to define a new datatype:
data MyInt = MyInt Int
We could then write appropriate code for this datatype. The problem
(and this is very subtle) is that this type is not truly isomorphic to
Int
: it has one more value. When we think of the type Int
,
we usually think that it takes all values of integers, but it really
has one more value: (pronounced "bottom"), which is used
to represent erroneous or undefined computations. Thus, MyInt
has not only values MyInt 0
, MyInt 1
and so on, but also
MyInt
. However, since datatypes can themselves be
undefined, it has an additional value: which differs from
MyInt
and this makes the types non-isomorphic. (See
the section on Bottom for more information on bottom.)
Disregarding that subtlety, there may be efficiency issues with this
representation: now, instead of simply storing an integer, we have to
store a pointer to an integer and have to follow that pointer whenever
we need the value of a MyInt
.
To get around these problems, Haskell has a newtype construction. A newtype is a cross between a datatype and a type synonym: it has a constructor like a datatype, but it can have only one constructor and this constructor can have only one argument. For instance, we can define:
newtype MyInt = MyInt Int
But we cannot define any of:
newtype Bad1 = Bad1a Int | Bad1b Double newtype Bad2 = Bad2 Int Double
Of course, the fact that we cannot define Bad2
as above is not a
big issue: we simply use type instead:
type Good2 = Good2 Int Double
or (almost equivalently) declare a newtype alias to the existing tuple type:
newtype Good2 = Good2 (Int,Double)
Now, suppose we've defined MyInt
as a newtype:
instance Ord MyInt where compare (MyInt i) (MyInt j) | odd i && odd j = compare i j | even i && even j = compare i j | even i = LT | otherwise = GT
Like datatype, we can still derive classes like Show
and Eq
over newtypes (in fact, I'm implicitly assuming we have derived
Eq
over MyInt
-- where is my assumption in the above code?).
Moreover, in recent versions of GHC (see
the section on Ghc), on newtypes, you are allowed to derive
any class of which the base type (in this case, Int
) is an
instance. For example, we could derive Num
on MyInt
to
provide arithmetic functions over it.
Pattern matching over newtypes is exactly as in datatypes. We can
write constructor and destructor functions for MyInt
as follows:
mkMyInt i = MyInt i unMyInt (MyInt i) = i
Datatypes
editWe've already seen datatypes used in a variety of contexts. This section concludes some of the discussion and introduces some of the common datatypes in Haskell. It also provides a more theoretical underpinning to what datatypes actually are.
Strict Fields
editOne of the great things about Haskell is that computation is performed lazily. However, sometimes this leads to inefficiencies. One way around this problem is to use datatypes with strict fields. Before we talk about the solution, let's spend some time to get a bit more comfortable with how bottom works in to the picture (for more theory, see the section on Bottom).
Suppose we've defined the unit datatype (this one of the simplest datatypes you can define):
data Unit = Unit
This datatype has exactly one constructor, Unit
, which takes no
arguments. In a strict language like ML, there would be exactly one
value of type Unit
: namely, Unit
. This is not quite so in
Haskell. In fact, there are two values of type Unit
. One
of them is Unit
. The other is bottom (written ).
You can think of bottom as representing a computation which won't halt. For instance, suppose we define the value:
foo = foo
This is perfectly valid Haskell code and simply says that when you
want to evaluate foo
, all you need to do is evaluate foo
.
Clearly this is an "infinite loop."
What is the type of foo
? Simply a
. We cannot say anything
more about it than that. The fact that foo
has type a
in
fact tells us that it must be an infinite loop (or some other such
strange value). However, since foo
has type a
and thus can
have any type, it can also have type Unit
. We could write, for
instance:
foo :: Unit foo = foo
Thus, we have found a second value with type Unit
. In fact, we
have found all values of type Unit
. Any other non-terminating
function or error-producing function will have exactly the same effect
as foo
(though Haskell provides some more utility with the
function error
).
This means, for instance, that there are actually four values
with type Maybe Unit
. They are: , Nothing
,
Just
and Just Unit
. However, it could be the fact
that you, as a programmer, know that you will never come across the
third of these. Namely, you want the argument to Just
to be
strict. This means that if the argument to Just
is
bottom, then the entire structure becomes bottom. You use an
exclamation point to specify a constructor as strict. We can define a
strict version of Maybe
as:
data SMaybe a = SNothing | SJust !a
There are now only three values of SMaybe
. We can see the
difference by writing the following program:
module Main where import System data SMaybe a = SNothing | SJust !a deriving Show main = do [cmd] <- getArgs case cmd of "a" -> printJust undefined "b" -> printJust Nothing "c" -> printJust (Just undefined) "d" -> printJust (Just ()) "e" -> printSJust undefined "f" -> printSJust SNothing "g" -> printSJust (SJust undefined) "h" -> printSJust (SJust ()) printJust :: Maybe () -> IO () printJust Nothing = putStrLn "Nothing" printJust (Just x) = do putStr "Just "; print x printSJust :: SMaybe () -> IO () printSJust SNothing = putStrLn "Nothing" printSJust (SJust x) = do putStr "Just "; print x
Here, depending on what command line argument is passed, we will do something different. The outputs for the various options are:
Example:
% ./strict a Fail: Prelude.undefined % ./strict b Nothing % ./strict c Just Fail: Prelude.undefined % ./strict d Just () % ./strict e Fail: Prelude.undefined % ./strict f Nothing % ./strict g Fail: Prelude.undefined % ./strict h Just ()
The thing worth noting here is the difference between cases "c" and
"g". In the "c" case, the Just
is printed, because this is
printed before the undefined value is evaluated. However, in
the "g" case, since the constructor is strict, as soon as you match
the SJust
, you also match the value. In this case, the value is
undefined, so the whole thing fails before it gets a chance to do
anything.
Classes
editWe have already encountered type classes a few times, but only in the context of previously existing type classes. This section is about how to define your own. We will begin the discussion by talking about Pong and then move on to a useful generalization of computations.
Pong
editThe discussion here will be motivated by the
construction of the game Pong (see the appendix on Pong for
the full code). In Pong, there are three things drawn on the screen:
the two paddles and the ball. While the paddles and the ball are
different in a few respects, they share many commonalities, such as
position, velocity, acceleration, color, shape, and so on. We can
express these commonalities by defining a class for Pong entities,
which we call Entity
. We make such a definition as follows:
class Entity a where getPosition :: a -> (Int,Int) getVelocity :: a -> (Int,Int) getAcceleration :: a -> (Int,Int) getColor :: a -> Color getShape :: a -> Shape
This code defines a typeclass Entity
. This class has five
methods: getPosition
, getVelocity
, getAcceleration
,
getColor
and getShape
with the corresponding types.
The first line here uses the keyword class to introduce a new typeclass. We can read this typeclass definition as "There is a typeclass 'Entity'; a type 'a' is an instance of Entity if it provides the following five functions: ...". To see how we can write an instance of this class, let us define a player (paddle) datatype:
data Paddle = Paddle { paddlePosX, paddlePosY, paddleVelX, paddleVelY, paddleAccX, paddleAccY :: Int, paddleColor :: Color, paddleHeight :: Int, playerNumber :: Int }
Given this data declaration, we can define Paddle
to be an
instance of Entity
:
instance Entity Paddle where getPosition p = (paddlePosX p, paddlePosY p) getVelocity p = (paddleVelX p, paddleVelY p) getAcceleration p = (paddleAccX p, paddleAccY p) getColor = paddleColor getShape = Rectangle 5 . paddleHeight
The actual Haskell types of the class functions all have included the
context Entity a =>
. For example, getPosition
has type
Entity a => a -> (Int,Int)
. However, it will turn out that many
of our routines will need entities to also be instances of Eq
.
We can therefore choose to make Entity
a subclass of Eq
:
namely, you can only be an instance of Entity
if you are already
an instance of Eq
. To do this, we change the first line of the
class declaration to:
class Eq a => Entity a where
Now, in order to define Paddle
s to be instances of Entity
we
will first need them to be instances of Eq
-- we can do this by
deriving the class.
Computations
editLet's think back to our original motivation for defining the
Maybe
datatype from the section on Datatypes-maybe. We
wanted to be able to express that functions (i.e., computations) can
fail.
Let us consider the case of performing search on a graph. Allow us to take a small aside to set up a small graph library:
data Graph v e = Graph [(Int,v)] [(Int,Int,e)]
The Graph
datatype takes two type arguments which correspond to
vertex and edge labels. The first argument to the Graph
constructor is a list (set) of vertices; the second is the list (set)
of edges. We will assume these lists are always sorted and that each
vertex has a unique id and that there is at most one edge between any
two vertices.
Suppose we want to search for a path between two vertices. Perhaps
there is no path between those vertices. To represent this, we will
use the Maybe
datatype. If it succeeds, it will return the list
of vertices traversed. Our search function could be written (naively)
as follows:
search :: Graph v e -> Int -> Int -> Maybe [Int] search g@(Graph vl el) src dst | src == dst = Just [src] | otherwise = search' el where search' [] = Nothing search' ((u,v,_):es) | src == u = case search g v dst of Just p -> Just (u:p) Nothing -> search' es | otherwise = search' es
This algorithm works as follows (try to read along): to search in a
graph g
from src
to dst
, first we check to see if these
are equal. If they are, we have found our way and just return the
trivial solution. Otherwise, we want to traverse the edge-list. If
we're traversing the edge-list and it is empty, we've failed, so we
return Nothing
. Otherwise, we're looking at an edge from u
to v
. If u
is our source, then we consider this step and
recursively search the graph from v
to dst
. If this fails,
we try the rest of the edges; if this succeeds, we put our current
position before the path found and return. If u
is not our
source, this edge is useless and we continue traversing the edge-list.
This algorithm is terrible: namely, if the graph contains cycles, it can loop indefinitely. Nevertheless, it is sufficient for now. Be sure you understand it well: things only get more complicated.
Now, there are cases where the Maybe
datatype is not
sufficient: perhaps we wish to include an error message together with
the failure. We could define a datatype to express this as:
data Failable a = Success a | Fail String
Now, failures come with a failure string to express what went wrong. We can rewrite our search function to use this datatype:
search2 :: Graph v e -> Int -> Int -> Failable [Int] search2 g@(Graph vl el) src dst | src == dst = Success [src] | otherwise = search' el where search' [] = Fail "No path" search' ((u,v,_):es) | src == u = case search2 g v dst of Success p -> Success (u:p) _ -> search' es | otherwise = search' es
This code is a straightforward translation of the above.
There is another option for this computation: perhaps we want not just one path, but all possible paths. We can express this as a function which returns a list of lists of vertices. The basic idea is the same:
search3 :: Graph v e -> Int -> Int -> [[Int]] search3 g@(Graph vl el) src dst | src == dst = [[src]] | otherwise = search' el where search' [] = [] search' ((u,v,_):es) | src == u = map (u:) (search3 g v dst) ++ search' es | otherwise = search' es
The code here has gotten a little shorter, thanks to the standard
prelude map
function, though it is essentially the same.
We may ask ourselves what all of these have in common and try to gobble up those commonalities in a class. In essence, we need some way of representing success and some way of representing failure. Furthermore, we need a way to combine two successes (in the first two cases, the first success is chosen; in the third, they are strung together). Finally, we need to be able to augment a previous success (if there was one) with some new value. We can fit this all into a class as follows:
class Computation c where success :: a -> c a failure :: String -> c a augment :: c a -> (a -> c b) -> c b combine :: c a -> c a -> c a
In this class declaration, we're saying that c
is an instance of
the class Computation
if it provides four functions:
success
, failure
, augment
and combine
. The
success
function takes a value of type a
and returns it
wrapped up in c
, representing a successful computation. The
failure
function takes a String
and returns a computation
representing a failure. The combine
function takes two previous
computations and produces a new one which is the combination of both.
The augment
function is a bit more complex.
The augment
function takes some previously given computation
(namely, c a
) and a function which takes the value of that
computation (the a
) and returns a b
and produces a b
inside of that computation. Note that in our current situation,
giving augment
the type c a -> (a -> a) -> c a
would have
been sufficient, since a
is always [Int]
, but we make it
more general this time just for generality.
How augment
works is probably best shown by example. We can
define Maybe
, Failable
and []
to be instances of
Computation
as:
instance Computation Maybe where success = Just failure = const Nothing augment (Just x) f = f x augment Nothing _ = Nothing combine Nothing y = y combine x _ = x
Here, success is represented with Just
and failure
ignores
its argument and returns Nothing
. The combine
function
takes the first success we found and ignores the rest. The function
augment
checks to see if we succeeded before (and thus had a
Just
something) and, if we did, applies f
to it. If we
failed before (and thus had a Nothing
), we ignore the function
and return Nothing
.
instance Computation Failable where success = Success failure = Fail augment (Success x) f = f x augment (Fail s) _ = Fail s combine (Fail _) y = y combine x _ = x
These definitions are obvious. Finally:
instance Computation [] where success a = [a] failure = const [] augment l f = concat (map f l) combine = (++)
Here, the value of a successful computation is a singleton list containing that value. Failure is represented with the empty list and to combine previous successes we simply catenate them. Finally, augmenting a computation amounts to mapping the function across the list of previous computations and concatenate them. we apply the function to each element in the list and then concatenate the results.
Using these computations, we can express all of the above versions of search as:
searchAll g@(Graph vl el) src dst | src == dst = success [src] | otherwise = search' el where search' [] = failure "no path" search' ((u,v,_):es) | src == u = (searchAll g v dst `augment` (success . (u:))) `combine` search' es | otherwise = search' es
In this, we see the uses of all the functions from the class
Computation
.
If you've understood this discussion of computations, you are in a
very good position as you have understood the concept of
monads, probably the most difficult concept in Haskell. In
fact, the Computation
class is almost exactly the Monad
class, except that success
is called return
, failure
is
called fail
and augment
is called >>=
(read "bind").
The combine
function isn't actually required by monads, but is
found in the MonadPlus
class for reasons which will become
obvious later.
If you didn't understand everything here, read through it again and then wait for the proper discussion of monads in the chapter Monads.
Instances
editWe have already seen how to declare instances of some simple classes;
allow us to consider some more advanced classes here. There is a
Functor
class defined in the Functor
module.
Note
The name "functor", like "monad" comes from category theory. There, a functor is like a function, but instead of mapping elements to elements, it maps structures to structures.
The definition of the functor class is:
class Functor f where fmap :: (a -> b) -> f a -> f b
The type definition for fmap
(not to mention its name) is very
similar to the function map
over lists. In fact, fmap
is
essentially a generalization of map
to arbitrary structures (and,
of course, lists are already instances of Functor
). However, we
can also define other structures to be instances of functors.
Consider the following datatype for binary trees:
data BinTree a = Leaf a | Branch (BinTree a) (BinTree a)
We can immediately identify that the BinTree
type essentially
"raises" a type a
into trees of that type. There is a
naturally associated functor which goes along with this raising. We
can write the instance:
instance Functor BinTree where fmap f (Leaf a) = Leaf (f a) fmap f (Branch left right) = Branch (fmap f left) (fmap f right)
Now, we've seen how to make something like BinTree
an instance of
Eq
by using the deriving keyword, but here we will do it by
hand. We want to make BinTree a
s instances of Eq
but
obviously we cannot do this unless a
is itself an instance of
Eq
. We can specify this dependence in the instance declaration:
instance Eq a => Eq (BinTree a) where Leaf a == Leaf b = a == b Branch l r == Branch l' r' = l == l' && r == r' _ == _ = False
The first line of this can be read "if a
is an instance of
Eq
, then BinTree a
is also an instance of Eq
". We
then provide the definitions. If we did not include the Eq a
=>
part, the compiler would complain because we're trying to use
the ==
function on a
s in the second line.
The "Eq a =>
" part of the definition is called the "context."
We should note that there are some restrictions on what can appear in
the context and what can appear in the declaration. For instance,
we're not allowed to have instance declarations that don't contain
type constructors on the right hand side. To see why, consider the
following declarations:
class MyEq a where myeq :: a -> a -> Bool instance Eq a => MyEq a where myeq = (==)
As it stands, there doesn't seem to be anything wrong with this definition. However, if elsewhere in a program we had the definition:
instance MyEq a => Eq a where (==) = myeq
In this case, if we're trying to establish if some type is an instance
of Eq
, we could reduce it to trying to find out if that type is
an instance of MyEq
, which we could in turn reduce to trying to
find out if that type is an instance of Eq
, and so on. The
compiler protects itself against this by refusing the first instance
declaration.
This is commonly known as the closed-world assumption. That is, we're assuming, when we write a definition like the first one, that there won't be any declarations like the second. However, this assumption is invalid because there's nothing to prevent the second declaration (or some equally evil declaration). The closed world assumption can also bite you in cases like:
class OnlyInts a where foo :: a -> a -> Bool instance OnlyInts Int where foo = (==) bar :: OnlyInts a => a -> Bool bar = foo 5
We've again made the closed-world assumption: we've assumed that the
only instance of OnlyInts
is Int
, but there's no reason
another instance couldn't be defined elsewhere, ruining our definition
of bar
.
Kinds
editLet us take a moment and think about what types are available in
Haskell. We have simple types, like Int
, Char
, Double
and so on. We then have type constructors like Maybe
which take
a type (like Char
) and produce a new type, Maybe Char
.
Similarly, the type constructor []
(lists) takes a type (like
Int
) and produces [Int]
. We have more complex things like
->
(function arrow) which takes two types (say Int
and Bool
) and produces a new type Int -> Bool
.
In a sense, these types themselves have type. Types like Int
have some sort of basic type. Types like Maybe
have a type which
takes something of basic type and returns something of basic type.
And so forth.
Talking about the types of types becomes unwieldy and highly
ambiguous, so we call the types of types "kinds." What we have been
calling "basic types" have kind "*
". Something of kind
*
is something which can have an actual value. There is also a
single kind constructor, ->
with which we can build more complex
kinds.
Consider Maybe
. This takes something of kind *
and produces
something of kind *
. Thus, the kind of Maybe
is * -> *
. Recall the definition of Pair
from
the section on Datatypes-pairs:
data Pair a b = Pair a b
Here, Pair
is a type constructor which takes two arguments, each
of kind *
and produces a type of kind *
. Thus, the kind of
Pair
is * -> (* -> *)
. However, we again assume
associativity so we just write * -> * -> *
.
Let us make a slightly strange datatype definition:
data Strange c a b = MkStrange (c a) (c b)
Before we analyze the kind of Strange
, let's think about what it
does. It is essentially a pairing constructor, though it doesn't pair
actual elements, but elements within another constructor. For
instance, think of c
as Maybe
. Then MkStrange
pairs
Maybe
s of the two types a
and b
. However, c
need not be Maybe
but could instead by []
, or many other
things.
What do we know about c
, though? We know that it must have kind
* -> *
. This is because we have c a
on the right hand
side. The type variables a
and b
each have kind *
as
before. Thus, the kind of Strange
is (* -> *) -> * -> * -> *
. That is, it takes a constructor (c
) of kind * -> *
together with two types of kind *
and produces something of kind
*
.
A question may arise regarding how we know a
has kind *
and
not some other kind k
. In fact, the inferred kind for
Strange
is (k -> *) -> k -> k -> *
. However, this requires polymorphism on the kind level, which is too complex, so we make a
default assumption that k = *
.
Note
There are extensions to GHC which allow you to specify the kind of constructors directly. For instance, if you wanted a different kind, you could write this explicitly:
data Strange (c :: (* -> *) -> *) a b = MkStrange (c a) (c b)
to give a different kind to Strange
.
The notation of kinds suggests that we can perform partial application, as we can for functions. And, in fact, we can. For instance, we could have:
type MaybePair = Strange Maybe
The kind of MaybePair
is, not surprisingly, * -> * -> *
.
We should note here that all of the following definitions are acceptable:
type MaybePair1 = Strange Maybe type MaybePair2 a = Strange Maybe a type MaybePair3 a b = Strange Maybe a b
These all appear to be the same, but they are in fact not identical as far as Haskell's type system is concerned. The following are all valid type definitions using the above:
type MaybePair1a = MaybePair1 type MaybePair1b = MaybePair1 Int type MaybePair1c = MaybePair1 Int Double type MaybePair2b = MaybePair2 Int type MaybePair2c = MaybePair2 Int Double type MaybePair3c = MaybePair3 Int Double
But the following are not valid:
type MaybePair2a = MaybePair2 type MaybePair3a = MaybePair3 type MaybePair3b = MaybePair3 Int
This is because while it is possible to partially apply type
constructors on datatypes, it is not possible on type synonyms. For
instance, the reason MaybePair2a
is invalid is because
MaybePair2
is defined as a type synonym with one argument and we
have given it none. The same applies for the invalid MaybePair3
definitions.
Class Hierarchies
editDefault
editwhat is it?