Calculus/Some Important Theorems< Calculus
This section covers three theorems of fundamental importance to the topic of differential calculus: The Extreme Value Theorem, Rolle's Theorem, and the Mean Value Theorem. It also discusses the relationship between differentiability and continuity.
Extreme Value TheoremEdit
Classification of ExtremaEdit
We start out with some definitions.
Maxima and minima are collectively known as extrema.
The Extreme Value TheoremEdit
The Extreme Value Theorem is a fundamental result of real analysis whose proof is beyond the scope of this text. However, the truth of the theorem allows us to talk about the maxima and minima of continuous functions on closed intervals without concerning ourselves with whether or not they exist. When dealing with functions that do not satisfy the premises of the theorem, we will need to worry about such things. For example, the unbounded function has no extrema whatsoever. If is restricted to the semi-closed interval , then has a minimum value of 0 at , but it has no maximum value since, for any given value , one can always find a larger value of for , for example by forming , where is the average of with 1. The function has a discontinuity at . fails to have any extrema in any closed interval around since the function is unbounded below as one approaches 0 from the left, and it is unbounded above as one approaches 0 from the right. (In fact, the function is undefined for . However, the example is unaffected if is assigned any arbitrary value.)
The Extreme Value Theorem is an existence theorem. It tells us that global extrema exist if certain conditions are met, but it doesn't tell us how to find them. We will discuss how to determine the extrema of continuous functions in the section titled Extrema and Points of Inflection.
Rolle's Theorem is important in proving the Mean Value Theorem. Intuitively it says that if you have a function that is continuous everywhere in an interval bounded by points where the function has the same value, and if the function is differentiable everywhere in the interval (except maybe at the endpoints themselves), then the function must have zero slope in at least one place in the interior of the interval.
Proof of Rolle's TheoremEdit
If is constant on , then for every , so the theorem is true. So for the remainder of the discussion we assume is not constant on .
Since satisfies the conditions of the Extreme Value Theorem, must attain its maximum and minimum values on . Since is not constant on , the endpoints cannot be both maxima and minima. Thus, at least one extremum exists in . We can suppose without loss of generality that this extremum is a maximum because, if it were a minimum, we could consider the function instead. Let with be a maximum. It remains to be shown that .
By the definition of derivative, . By substituting , this is equivalent to . Note that for all since is the maximum on .
since it has non-positive numerator and negative denominator.
since it has non-positive numerator and positive denominator.
The limits from the left and right must be equal since the function is differentiable at , so .
Mean Value TheoremEdit
The Mean Value Theorem is an important theorem of differential calculus. It basically says that for a differentiable function defined on an interval, there is some point on the interval whose instantaneous slope is equal to the average slope of the interval. Note that Rolle's Theorem is the special case of the Mean Value Theorem when .
In order to prove the Mean Value Theorem, we will prove a more general statement, of which the Mean Value Theorem is a special case. The statement is Cauchy's Mean Value Theorem, also known as the Extended Mean Value Theorem.
Cauchy's Mean Value TheoremEdit
To prove Cauchy's Mean Value Theorem, consider the function
Since both and are continuous on and differentiable on , so is .
Since (see the exercises), Rolle's Theorem tells us that there exists some number such that . This implies that
which is what was to be shown.
Differentiability Implies ContinuityEdit
If exists then is continuous at . To see this, note that . But
This imples that or , which shows that is continuous at .
The converse, however, is not true. Take , for example. is continuous at 0 since and and , but it is not differentiable at 0 since but .