A-level Mathematics/AQA/MFP1
Roots and coefficients of a quadratic equation
editGiven the equation ax2+bx+c=0 has roots and :
Useful results
edit
This last one comes from that when you add two fractions. Generally the formula is:
Complex Numbers
editA complex number is different 'type' of number to what we'd normally think of as a number. There are infinitely many complex numbers, like there are infinitely 'normal', or real numbers. To clarify, a real number is any number on the 'number line' : integers (...-2, -1, 0, 1, 2...), rational numbers (can be written as fractions, such as 1.2, 5.75), irrational numbers (can't be written as fractions, such as π, √2) - they're all real numbers. Complex numbers 'go beyond' these ordinary numbers.
Consider the discriminant of a quadratic - from the formula: . Remember, the discriminant of a quadratic determines the nature of its roots (solutions). A discriminant ≥ 0 implies that there are real root(s), and a discriminant < 0 implies that there are no real roots. Why is this?
Recall the quadratic formula:
From this, we can see if , then involves the square root of a negative number. Taking the quadratic as an example, we can see no solution for . We need , so what can be? It can't be 1, because 1 squared is 1. It can't be -1, either, as -1 squared is also 1. What can we do?
The Imaginary Unit, i
editTo get round this, we 'invent' a number, called . does not 'exist' as a real number - so you cannot have apples in your hand. Thus is dubbed an imaginary number, which is what the i stands for. The key property of is that . So in our above example, the solution was . Right?
Well, not quite. We can use multiples of : 2i, 3i, 4i, 0.4i, -0.4i, -1.4i... . We can have positive or negative, integer, rational or irrational multiples of . Let's keep it simple and think of, . What's ?
The answer is -1. Why? In short, a minus times a minus makes a plus, and times makes -1 - so the result is just -1. If this is a little confusing, think of the problem as finding , and then substituting and . In short, . Putting this to use in the problem above gives us two (non-real) solutions: and .
In the same way that we could say the square root of 1 is 1 or -1, the square root of -1 is i or -i.
Square Roots of negative numbers
editWe've already looked at . But this isn't too useful by itself alone. What, for example, is equal to? We can treat this problem in the same way we simplify surds.
If ab = -2, we could let a=-1, and b =2.
- powers of i
- a + bi
- addition, subtraction
- multiplication
- 'division'
- conjugates, z, z* notation
- conjugates as roots of a quadratic.
- considering real and imaginary parts
- lead into complex numbers from imaginary.
(image and caption of mandlebrot set, mention use of complex numbers)
The Power Tower of i
editPart of the definition of i is that , and based only on this fact alone we can find i to the power of any integer.
Let's go up a power. What's ? Well, we can write as . We already know that , so this simplifies to . Easy!
Let's try the next power - . We treat this in the same way, writing . And it's fairly easy to substitute to arrive at the conclusion that . This makes sense, when you think about it: what do you get if you square both sides of ?
Now we can climb back down the power tower. is just i - there's nothing complex there. If you wanted to, you could let , and the solve for x in .
We can also use this to find - let's denote this by y. Then:
Complex Numbers, more formally
editComplex numbers are numbers of the form , where a and b are both real numbers, and i is the imaginary unit. We call a the re
So if you were to have the quadratic formula . You would get . Knowing that It would simplify down to and then to where the 1 is the real part and the 8i is the imaginary part.
Complex Arithmetic
editAddition and Subtraction
editAddition and subtraction of complex numbers is fairly intuitive: you sum the real parts and imaginary parts separately. (Or condense into on expression and group like terms.)
Example (adding)
Example (subtracting)
Multiplication
editThe easiest way to multiply complex numbers is to form an expression with the numbers in brackets and then to expand the brackets and simplify. For example:
Expanding the brackets gives;
Then collect like terms and replace with ;
Therefore the final result is;
Division
editDivision is not covered in FP1, but is covered in other Further Pure modules.
Complex Conjugates
editEach complex number has a complex conjugate which is formed by taking the original complex number and changing the sign of the imaginary part. For example, the complex conjugate of would be . These numbers are often referred to as a conjugate pair.
The conjugate of z is written as z*.
Conjugate pairs have the property that when one is subtracted from the other, the result is purely imaginary. Also if they are added or multiplied together the result is a real number. This means that for a quadratic equation with real coefficients but imaginary roots, the roots will be a pair of complex conjugates.
Example:
This equation cannot be factorised, therefore we use the quadratic formula ( ) to solve it;
You will find that the portion of the equation under the root sign is negative, this means that the roots of the quadratic are not real.
Write the root in terms of i and simplify the surd.
Now you can cancel the fraction to give the answers.
Solving Equations with Complex Numbers
editInequalities
edit- Multiplying by the square of the denominator to ensure a positive multiplication
- Critical Values
- Truth tables and graphs of inequalities
- Factorising
Trigonometry
edit- Special angles for sin, cos, tan
- Radians
- Finding general solutions as opposed to specific solutions
- Use of sin/cos === tan, cos^2+sin^2 === 1
Matrices and Transformations
edit- Definition of matrices
- Order of a matrix
- Matrix addition, subtraction
- Matrix multiplication
- When is it defined
- Using a matrix to represent a transformation
- Reflection, Reflection, Enlargement
- Composite Transformations
- Formulae for AC rotation through theta, reflection in y = x * tan theta
Linear Laws
edit- Log Laws
- Use of log laws to reduce to a linear relationship for
- y=a^x + b
- y=x^a + b
Series
editSimply put, a series is the result of adding the terms of a sequence together, for example the series produced by summing the terms of the sequence 2n+1 would be;
This is an infinite sequence as it has an infinite number of terms. However if we limit it to the first 5 terms of the sequence we create a finite sequence. This is much easier to work with and find the sum, thus;
To write this simply we use sigma notation.
Sigma Notation
editThe capital Greek letter sigma, is used to mean 'sum of'. It is written with the range of the variable above and below it (maximum value above and minimum below) and the letter representing the variable to be changed below it. Therefore the second example shown above would be written;
The first example shown above can also be written using sigma notation, with the sign for infinity ) ) above the sigma.
Summing with an initial counter value not 1
editIf the number under the sigma is not 1 then you should split expression, using two sigma signs, for example:
becomes;
Note that in the second part of the expression, the maximum value of the variable is one less than the minimum in the original expression.
Forumlae for r, r^2, r^3
editSpecial formulae are used to find the values of series with variables above the sigma.
Formula for r
editThe expression to add the first n natural numbers can be written using sigma notation thus;
This can be written as an expression using only n;
Formula for
editThe expression to add the first n square numbers can be written using sigma notation;
It too can be written as an expression in terms of n
Formula for
editThe expression to add the first n cube numbers can be written using sigma notation;
It too can be written as an expression in terms of n
Manipulating Sigma Notation
editUsing combinations of the formulae above we can find values for more complicated expressions. For example;
Firstly, you can split the terms of the expression, you can also take the coefficients of the terms before the sigma signs.
Using the above formulae you can replace the first 2 terms with their equivalent expressions. For the final term, you see that it is the sum of ten sevens, or
Now this expression can be solved like any other;
Calculus
edit- First-principals approach to differentiation
- Difference quotient
- Improper Integration
- Why improper
- Does the integral exist?
Numerical Methods
editRational Functions
edit- Definition, examples
- Asymptote - definition
- How to find vertical and horizontal asymptotes.
- Sketching functions by considering
- Asymptotes
- x- and y-intercepts
- Behaviour as approaching an asymptote
Further Functions
edit- Using the discriminant of a quadratic to find maxima and minima
- NB Differentiation by Quotient rule is explicitly excluded
Hyperbolae, Parabolae and Ellipses
edit- Definition, examples of, generalised formulae of
- Transformations of
- Asymptotes of hyperbolae
- Relation of an ellipse to a circle
- Foci.