- Let be a set of n positive numbers. The Stieltjes continued fraction is an expression of the form
The function and its reciprocal define all rational n-to-1 maps of the right half of the complex plane onto itself,
since
- The function is determined by the pre-image set of the point {z = 1}, since
and a complex polynomial is determined by its roots up to a multiplicative constant by the fundamental theorem of algebra.
Let be the elementary symmetric functions of the set . That is,
- Then the coefficients of the continued fraction are the pivots in the Gauss-Jordan elimination algorithm of the following n by n square Hurwitz matrix:
and, therefore, can be expressed as the ratios of monomials of the determinants of its blocks.
Exercise 1 :
Prove that
Exercise 2 :
Let A be a diagonal matrix with the alternating in sign diagonal entries:
and D the (0,1)-matrix
Prove that the continued fraction evaluated at a point equals to 1 if and only if is an eigenvalue of the matrix AD.
Exercise 3 :
Use Exercise 1 to prove that