# UMD Analysis Qualifying Exam/Jan11 Real

## Problem 1Edit

Let be an absolutely continuous function on [0,1] with . Prove that . |

### SolutionEdit

Since is (absolutely) continuous on [0,1] with then there exists some .

Since then for any there exists some such that for any finite collection of disjoint intervals such that if then .

Then for any such collection of intervals described above, we have .