## Introduction

Traditional division method (TD), kijohou, guī chúfǎ (帰除法), is one of the two main methods of division used with the abacus. This method makes use of both the multiplication table and a specific division table and has been the standard method studied with the abacus for at least 4 centuries, losing popularity in the 1930s. As a digit-by-digit or slow division algorithm, has been introduced in the previous chapter, where its special characteristic is revealed: it does not require thinking but only following some rules. This document is an introduction to its use on the abacus and it is assumed that the reader is already proficient in the modern division (MD) method.

## The division table

In the previous chapter Modern and traditional division; close relatives, the following division table has been introduced

 1/9>1+1 2/9>2+2 3/9>3+3 4/9>4+4 5/9>5+5 6/9>6+6 7/9>7+7 8/9>8+8 9/9>9+9 1/8>1+2 2/8>2+4 3/8>3+6 4/8>5+0 5/8>6+2 6/8>7+4 7/8>8+6 8/8>9+8 1/7>1+3 2/7>2+6 3/7>4+2 4/7>5+5 5/7>7+1 6/7>8+4 7/7>9+7 1/6>1+4 2/6>3+2 3/6>5+0 4/6>6+4 5/6>8+2 6/6>9+6 1/5>2+0 2/5>4+0 3/5>6+0 4/5>8+0 5/5>9+5 1/4>2+2 2/4>5+0 3/4>7+2 4/4>9+4 1/3>3+1 2/3>6+2 3/3>9+3 1/2>5+0 2/2>9+2 1/1>9+1

where in each cell the result of the Euclidean division

${\displaystyle (10\times a)/b=q,r}$

(${\displaystyle q}$ : quotient, ${\displaystyle r}$ : remainder, ${\displaystyle a,b}$  digits from 1 to 9) is expressed in the form ${\displaystyle a/b>q+r}$  for reasons that we will see below. This means that the following hold:

${\displaystyle 10a=q\cdot b+r}$

The table has three zones corresponding to the following: If the divisor has n figures and we compare it with the first n digits (from the left) of the dividend, with added trailing  zeros if necessary, three cases can occur:

1. the dividend is greater than or equal to the divisor (ex. ${\displaystyle 770/689}$ )
2. the dividend is less than the divisor and the first digit of the divisor is equal to the first digit of the dividend (ex. ${\displaystyle 670/689}$ )
3. the dividend is less than the divisor and the first digit of the divisor is greater than the first digit of the dividend (ex. ${\displaystyle 570/689}$ )

The blank cells below the diagonal of the division table above correspond to case 1. They could be filled in the style of the tables that can be seen elsewhere[1], but we leave them empty for simplicity. If during the division we fall into this zone, we will proceed, for now, simply by revising up the previous quotient digit as we will see in the examples that follow.

The diagonal elements (in gray) correspond to the case 2 and can only occur if the divisor has at least two digits.

Finally, the other non-diagonal elements correspond to the case 3, which can be considered the most important to study.

There is no doubt that memorizing the division table takes time and effort and that you want to know if the traditional method of division is right for you before investing so much time and effort. Fortunately, the division by nine, five, and two tables are remarkably simple and can be memorized almost instantly (see below), as well as diagonal elements for multi digit divisors. This means that we can learn this traditional technique using divisors that start with only 9, 5 or 2 without much effort and thus be able to decide whether it is worth spending time learning the whole table or not. In what follows we will use examples based on such divisors.

Easy-to-memorize division rules
Diagonal Divide by 9 Divide by 5 Divide by 2
1/1>9+1 1/9>1+1 1/5>2+0 1/2>5+0
2/2>9+2 2/9>2+2 2/5>4+0
3/3>9+3 3/9>3+3 3/5>6+0
4/4>9+4 4/9>4+4 4/5>8+0
5/5>9+5 5/9>5+5
6/6>9+6 6/9>6+6
7/7>9+7 7/9>7+7
8/8>9+8 8/9>8+8
9/9>9+9

## Why do the division rules include remainders?

Suppose we are going to divide 35 by 9, the 3/9>3+3 rule tells us that we must use 3 as an interim quotient and the next step will be to subtract the chunk 3✕9=27 from 35, leaving a remainder of 8. If we also memorize the remainders, we can save this multiplication step as follows: we cancel, clear or erase the first digit of the dividend, in this case 3, then we add the remainder (3) to the next figure (5) of the dividend. In this way, we obtain the same result but without using the multiplication table. With one-digit divisors we will never have to resort to the multiplication table, and in the case of divisors with several figures, proceeding in the same way, we will save one of the necessary multiplications. We will see it on the abacus below, but first we need a few words about how we are going to arrange the division on the abacus.

## Modern Division Arrangement (MDA)

While using MDA you can use the same rules you already know about the unit rod if you need them.

Let us see the 35÷9 case  from the above section, first without using the (rule) remainders

35÷9 without using the (rule) remainders
Abacus Comment
ABCDEFGH
9     35 Divisor in A, dividend in GH, rule: 3/9>3+3
+3 enter quotient 3 in E
9    335
-27 subtract chunk 3✕9=27 from GH
9    3 8 new remainder/dividend in H
... ...

And now using the remainders

35÷9 using the (rule) remainders
Abacus Comment
ABCDEFGH
9     35 Divisor in A, dividend in GH, rule: 3/9>3+3
+3 enter quotient 3 in E
9    335
-3 clear first dividend digit in G
9    3 5
9     +3 add remainder 3 to H
9    3 8 new remainder/dividend in H
... ...

That is:

When using MDA, the rule a/b>q+r must be read: “write q as interim quotient digit to the left, clear a and add r to the right”

## One digit divisors

The number 123456789 has traditionally been used to demonstrate the use of multiplication and division tables in ancient Chinese[3] and Japanese works[4][5]. Here we will use it with the “easy divisors” 9, 5 and 2.

### Example 123456789÷9=13717421

123456789÷9=13717421
Abacus Comment
ABCDEFGHIJ (Divisor not indicated)
123456789 Rule 1/9>1+1
+1 enter quotient 1 into A
-1 clear B
1 33456789 Rule 3/9>3+3
13 6456789 Rule 6/9>6+6
1361056789
+1-9 revising up
137 156789 Rule 1/9>1+1
1371 66789 Rule 6/9>6+6
1371612789
+1-9 revising up
13717 3789 Rule 3/9>3+3
1371731089
+1-9 revising up
137174 189 Rule 1/9>1+1
1371741 99
+1-9 revising up
1371742  9
+1-9 revising up
13717421 Done!

### Example 123456789÷5=24691357.8

123456789÷5=24691357.8
Abacus Comment
ABCDEFGHIJ (Divisor not indicated)
123456789 Rule 1/5>2+0
2 23456789 Rule 2/5>4+0
24 3456789 Rule 3/5>6+0
246 456789 Rule 4/5>8+0
2468 56789
+1-5 revising up
2469  6789
+1-5 revising up
24691 1789 Rule 1/5>2+0
246912 789
+1-5 revising up
246913 289 Rule 2/5>4+0
2469134 89
+1-5 revising up
2469135 39 Rule 3/5>6+0
24691356 9
+1-5 revising up
24691357 4 Rule 3/5>6+0
246913578 Done!

### Example 123456789÷2=61728394.5

123456789÷2=61728394.5
Abacus Comment
ABCDEFGHIJ (Divisor not indicated)
123456789 Rule 1/2>5+0
5 23456789
+1-2 revising up
6  3456789
+1-2 revising up
61 1456789 Rule 1/2>5+0
615 456789
+2-4 revising up twice
617  56789
+2-4 revising up twice
6172 16789 Rule 1/2>5+0
61725 6789
+3-6 revising up three times
61728  789
+3-6 revising up twice
617283 189 Rule 1/2>5+0
6172835 89
+4-8 revising up four times
6172839  9
+4-8 revising up four times
61728394 1 Rule 1/2>5+0
617283945 Done!

## Multi Digit divisors

Consider, for example, ${\displaystyle 359936/9728=37}$ , in this case it is convenient to think of the divisor as made up of a divider, the first digit, followed by a multiplier, the rest of the digits of the divisor, that is, ${\displaystyle 9728=dmmm}$ , where ${\displaystyle d}$  is the divider (9) and ${\displaystyle mmm}$  is the multiplier (728). The Chinese and Japanese names for this division method (帰除 Guīchú in Chinese, 帰除法 Kijohou in Japanese) refer to this: 帰, Guī, Ki is the header and 除, chú, jo is the multiplier[6].

In this case, the way to act is as follows:

1. First we consider only the divider ${\displaystyle d}$  and do exactly the same as in the case of the single digit divisor i.e. we follow the division rule: get the interim quotient ${\displaystyle q}$  and add the remainder (from the rule) to the adjacent column
2. Then we subtract the chunk ${\displaystyle q\times {\text{multiplier}}}$  from the remainder if we can; otherwise we have to revise down ${\displaystyle q}$  and restore ${\displaystyle d}$  to the remainder using the following rules:
Rules to revise down (two-digit divisors)
While dividing by Revise q to Add to remainder
1 q-1 +1
2 q-1 +2
3 q-1 +3
4 q-1 +4
5 q-1 +5
6 q-1 +6
7 q-1 +7
8 q-1 +8
9 q-1 +9

These rules are for two-digit divisors, for divisors with more digits things may be more complicated, as in MD (see example ${\displaystyle 23712/5928}$  below). Let us see the above case

### Example 359936÷9728=37

359936÷9728=37
Abacus Comment
ABCDEFGHIJKLM
9728   359936 Rule 3/9>3+3
9728  3 89936 enter 3 to G, clear H and add 3 to I
-2184 subtract chunk 3✕multiplier 3✕728=2184a from I-L
9728  3 68096 Rule 6/9>6+6
9728  3614096 enter 6 to H, clear I and add 6 to J
-4368 subtract chunk 6✕multiplier 6✕728=4368 from J-M
9728  36 9728 revising up
+1-9728
9728  37 Done!

Note: ^a This is an abbreviated notation meaning that 3✕7, 3✕2 and 3✕8 have to be subtracted from IJ, JK, and KL respectively.

### Example 235÷59=3.98…

235÷59=3.98…
Abacus Comment
ABCDEFGHIJ
59   235 Rule 2/5>4+0
59  4 35 enter 4 to E, clear F and add 0 to G
-36 cannot subtract chunk 4✕multiplier 4✕9=36 from GH!
-1+5 revise down following above rules
59  3 85
-27 subtract chunk 3✕multiplier 3✕9=27 from GH
59  3 58 Rule 5/5>9+5
59  3913 enter 9 to F, clear G and add 5 to H
-81 subtract chunk 9✕multiplier 9✕9=81 from HI
59  39 49 Rule 4/5>8+0
... etc.

### Example 23711÷5928=3,9998…

Caption text
Abacus Comment
ABCDEFGHIJKLMN
5928   23711 Rule 2/5>4+0
5928  4 3711 enter 4 to G, clear H and add 0 to I
-36 subtract 4✕9=36 from IJ
5928  4  111
-8 subtract 4✕2=8 from JK
5928  4   31
-32 cannot subtract 4✕8=32 from KL!
-1+592 revise down and restore the subtracted excess to IJK
5928  3 5951
-24 continue normally, subtract 3✕8=24 from KL
5928  3 5927 Rule 5/5>9+5
... etc.

As commented above, there are two basic ways of arranging general division problems. Let us see them side by side:

• Modern division arrangement (MDA), as explained by Kojima[2],
MDA 25÷5=5
Abacus Comment
ABCDEF
5   25 Dividend starting in E
5  5 After division quotient begins in D

• Traditional division arrangement (TDA), as used in ancient books since the times of counting rods[7] to the first part of the 20th century[8],
TDA 25÷5=5
Abacus Comment
ABCDEF
5   25 25÷5=5 Dividend starting in E
5   5 After division quotient begins in E

So far we have used MDA with the traditional division without any problem. TDA, however, is problematic with any division method, the traditional one included. This troublesome nature is due to a collision between the divisor and the dividend/remainder that occurs frequently (that is, both require the simultaneous use of the same column), and special techniques or abaci are needed to deal with this collision. Despite this, the TDA has been used for centuries in conjunction with the traditional method of division, at least since the 13th century, while the MDA has been shelved until modern times. It is clear that certain advantages can be recognized to TDA, but it is not so clear that they are enough to justify its historical use:

• It uses one rod less
• Result does not displace too much to the left as in MDA, which is of interest in the case of chained operations. This and the above points makes TDA more suitable to abacuses with a small number of rods, like the traditional 13-rod suanpan/soroban.
• It saves some finger movements; for instance, in the operation 6231÷93=67 using traditional (chinese) division, I count 14 finger movements with TDA versus 24 with MDA.
• Hand displacements are shorter.
• It is less prone to errors as less rods are skipped.

The way to avoid the mentioned collision is to accept that the first column of the dividend/remainder, after the application of Chinese division rules, can overflow and temporarily accept a value greater than 9 (up to 18), while providing some mechanism to deal with such an overflow. Interestingly enough, it seems that no ancient text explains how to do the latter, but we will do it in chapter: Dealing with overflow!.

In the case of a 5+2 or 5+3 abacus we can use the additional upper bead(s) to represent values from 10 to 20, using the suspended bead (懸珠 xuán zhū in Chinese, kenshu in Japanese) in the 5+2 case .

The third or suspended bead is expected to be used only in about 1% of cases, which justifies the adoption of the 5+2 model as standard instead of the 5+3. (If you are interested in using TDA on any abacus, head over to the Dealing with overflow chapter to see how)

When using TDA, the rule a/b>q+r must be read: “change a into q as interim quotient digit and add r to the right”

For examples of TD using TDA, refer to the Traditional division examples chapter.

## About the efficiency of TD

As you can see in the examples with single digit divisors, TD efficiency deteriorates as the divisor starts with lower figures in the sense that we have to revise up more frequently. We can say that the efficiency is zero when the divisor starts with 1; in fact, we don't even have division rules except 1/1>9+1 (which is statistically excessive, see chapter: Learning the division table). For this last case, the trick is to divide by 2 in situ (chapter: Division by powers of two) both divisor and dividend, which is very fast, and proceed to divide both results normally; now the divisor begins with a digit between 5 and 9. for example: ${\displaystyle 128/16}$

Caption text
Abacus Comment
ABCDEFGHI
16    128 Divide in situ by 2
8     64 Rule 6/8>7+4
8    7 8
+1-8 revising up
8    8 Done!

${\displaystyle 128/16=(128/2)/(16/2)=64/8=8}$

In other cases, our intuition and experience with MD could help us.

This lower efficiency of TD compared to MD is the price to pay to save us the mental work of deducting the interim quotient figure that we have to try.

## References

1. "割り算九九". Japanese Wikipedia. {{cite web}}: Unknown parameter |Language= ignored (|language= suggested) (help); Unknown parameter |accesdate= ignored (|access-date= suggested) (help); Unknown parameter |trans_title= ignored (|trans-title= suggested) (help)
2. a b Kojima, Takashi (1954), The Japanese Abacus: its Use and Theory, Tokyo: Charles E. Tuttle Co., Inc., ISBN 978-0-8048-0278-9
3. Xú Xīnlǔ (徐心魯) (1993) [1573]. Pánzhū Suànfǎ (盤珠算法) (in Chinese). Zhōngguó kēxué jìshù diǎnjí tōng huì (中國科學技術典籍通彙). {{cite book}}: Unknown parameter |trans_title= ignored (|trans-title= suggested) (help)
4. Yoshida, Mitsuyoshi (吉田光由) (1634). Jinkoki (塵劫記) (in Japanese). {{cite book}}: Unknown parameter |trans_title= ignored (|trans-title= suggested) (help)
5. Shinoda, Shosaku (篠田正作) (1895). Jitsuyo Sanjutsu (実用算術) (in Japanese). {{cite book}}: Unknown parameter |trans_title= ignored (|trans-title= suggested) (help)
6. Lisheng Feng (2020), "Traditional Chinese Calculation Method with Abacus", in Jueming Hua; Lisheng Feng (eds.), Thirty Great Inventions of China, Jointly published by Springer Publishing and Elephant Press Co., Ltd, ISBN 978-981-15-6525-0
7. Zhū Shìjié 朱士傑 (1993) [1299]. Suànxué Qǐméng (算學啟蒙) (in Chinese). Zhōngguó kēxué jìshù diǎnjí tōng huì (中國科學技術典籍通彙). {{cite book}}: Unknown parameter |trans_title= ignored (|trans-title= suggested) (help)
8. Kwa Tak Ming (1922), The Fundamental Operations in Bead Arithmetic, How to Use the Chinese Abacus (PDF), San Francisco: Service Supply Co.