For this project, all the information was set in front of us, and we had to translate that information into several mathematical equations. They started as word problems you had to change into an algebraic equation, or numbers. An example of this is when the word problem states “The sum of a certain quantity P together with it’s two third, and its half, becomes 234. What is the quantity of You must take that and turn it into a solvable equation.

First of all, we know that sum is related to addition, Hereford no subtraction or multiplication will be used. So, P together with it’s two third and it’s half, equals 234. This translates to P + 2/UP + h P = 234. An another example of translating an equation could be times it’s half, minus 30 equals 100. ” To translate this, start with the term times, which means multiplication. It would also include subtraction, hinted to by the “minus 30”. Then begin to write out the equation. Y* 1/AY – 30 = 100. Now to solve an equation, follow PAMPAS, or do everything in order.

You begin with solving things in parentheses. If our equation is (-3+4) + xx- 12, then you’d begin with (-3+4), which would equal 1. The equation would then be 1 + xx = xx -12. dsdssssssssssssssssssssssssssssssssssssssFollowing parentheses is exponents. Being there no exponents in this equation, you would move onto the next step, and that would be multiplication or division. Do these in the order they appear. There isn’t any multiplication or division in this problem not involving variables, so we’ll wait until the end. Next is addition or subtraction. Once again, do these in the order they appear.

Whatever you do to one side, you must do to the other. First we’ll start by adding 12 to both sides resulting in 13 + xx. Then subtract xx from both sides. You’ll find it comes out to 13 = xx. Finally, divide both sides by 16 and your answer will be 0. 8125. Now, let’s go back to our previous problem P + 2/UP + h P = 234, and begin to solve it. Let’s start by adding all like terms together. It would result in 2 1/6 P = 234. Now, there aren’t any parentheses, exponents, multiplication, division, addition, or subtraction steps to do, so divide 234 y 2 1/6.

The final answer is P = 108. In this project, we also used formulas. Formulas are equations in which you plug in what you have to find what you’re missing, such as area, perimeter, slope, or in the case of the project, volume. In the case of this problem, we have the volume, length, and width, of a pyramid. We had to find the height. The formula for volume is V = (Y)law, and to find the height, you had to divide the volume by all of these. The volume for this problem is 18,069,333. 3333 cubits cubed. Divide 18,069,333. 33 by 1/2 to get 54,208,000. Then divide that by the length of the pyramid to get 123,200. Finally divide that by the width of 440 to get the height of 280. To check your answer, use the formula, and plug in all of the numbers to see if you get the correct volume. V = 440 * 440 = 193,600 * 280 = 54,208,000. Finally multiply that by (1/2) to get 18,069,333. 3333, the correct answer. Let’s try another. The formula to find the area of a rectangle is A = 1 *w. Say we have a rectangle with a perimeter of 24, with one side being 8.

If one side is 8, on a cetacean, that means the opposite side is also 8. Then take the remaining 8, divide by two to get 4. Our length is 8, and our width is 4. To find the area, plug these numbers into the formula. A = 8 * 4, A = 32. Through this project, we’ve learned how to translate equations, then solve them, and finally, see if we need to use a formula on them, all very important math skills. After this project, I can strongly conclude that “KAREE AL-JAB” is none other than ABA, whose favorite number is -20, the same number as what the Text Message puzzle equals out to.