Projective Geometry/Classic/Projective Transformations/Transformations of the projective line
Let X be a point on the xaxis. A projective transformation can be defined geometrically for this line by picking a pair of points P, Q, and a line m, all within the same xy plane which contains the xaxis upon which the transformation will be performed.
Points P and Q represent two different observers, or points of view. Point R is the position of some object they are observing. Line m is the objective world which they are observing, and the xaxis is the subjective perception of m.
Draw line l through points P and X. Line l crosses line m at point R. Then draw line t through points Q and R: line t will cross the xaxis at point T. Point T is the transform of point X [Paiva].
Analysis
editThe above is a synthetic description of a onedimensional projective transformation. It is now desired to convert it to an analytical (Cartesian) description.
Let point X have coordinates (x_{0},0). Let point P have coordinates . Let point Q have coordinates . Let line m have slope m (m is being overloaded in meaning).
The slope of line l is
so an arbitrary point (x,y) on line l is given by the equation
 ,
On the other hand, any point (x,y) on line m is described by
The intersection of lines l and m is point R, and it is obtained by combining equations (1) and (2):
Joining the x terms yields
and solving for x we obtain
x_{1} is the abscissa of R. The ordinate of R is
Now, knowing both Q and R, the slope of line n is
We want to find the intersection of line n and the xaxis, so let
The value of λ must be adjusted so that both sides of vector equation (3) are equal. Equation (3) is actually two equations, one for abscissas and one for ordinates. The one for ordinates is
Solve for lambda,
The equation for abscissas is
which together with equation (4) yields
which is the abscissa of T.
Substitute the values of x_{1} and y_{1} into equation (5),
Dissolve the fractions in both numerator and denominator:
Simplify and relabel x as t(x):
t(x) is the projective transformation.
Transformation t(x) can be simplified further. First, add its two terms to form a fraction:
Then, define the coefficients α, β, γ and δ to be the following
Substitute these coefficients into equation (6), in order to produce
This is the Möbius transformation or linear fractional transformation.
Inverse transformation
editIt is clear from the synthetic definition that the inverse transformation is obtained by exchanging points P and Q. This can also be shown analytically. If P ↔ Q, then α → α′, β → β′, γ → γ′, and δ → δ′, where
Therefore if the forwards transformation is
then the transformation t′ obtained by exchanging P and Q (P ↔ Q) is:
Then
 .
Dissolve the fractions in both numerator and denominator of the right side of this last equation:

 .
Therefore t′(x) = t^{−1}(x): the inverse projective transformation is obtained by exchanging observers P and Q, or by letting α ↔ δ, β → −β, and γ → −γ. This is, by the way, analogous to the procedure for obtaining the inverse of a twodimensional matrix:
where Δ = α δ − β γ is the determinant.
Identity transformation
editAlso analogous with matrices is the identity transformation, which is obtained by letting α = 1, β = 0, γ = 0, and δ = 1, so that
Composition of transformations
editIt remains to show that there is closure in the composition of transformations. One transformation operating on another transformation produces a third transformation. Let the first transformation be t_{1} and the second one be t_{2}:
The composition of these two transformations is
Define the coefficients α_{3}, β_{3}, γ_{3} and δ_{3} to be equal to
Substitute these coefficients into to obtain
Projections operate in a way analogous to matrices. In fact, the composition of transformations can be obtained by multiplying matrices:
Since matrices multiply associatively, it follows that composition of projections is also associative.
Projections have: an operation (composition), associativity, an identity, an inverse and closure, so they form a group.
The crossratio defined by means of a projection
editLet there be a transformation t_{s} such that t_{s}(A) = , t_{s}(B) = 0, t_{s}(C) = 1. Then the value of t_{s}(D) is called the crossratio of points A, B, C and D, and is denoted as [A, B, C, D]_{s}:
Let
then the three conditions for t_{s}(x) are met when
Equation (7) implies that , therefore . Equation (8) implies that , so that . Equation (9) becomes
which implies
Therefore
In equation (10), it is seen that t_{s}(D) does not depend on the coefficients of the projection t_{s}. It only depends on the positions of the points on the "subjective" projective line. This means that the crossratio depends only on the relative distances among four collinear points, and not on the projective transformation which was used to obtain (or define) the crossratio. The cross ratio is therefore
Conservation of crossratio
editTransformations on the projective line preserve cross ratio. This will now be proven. Let there be four (collinear) points A, B, C, D. Their crossratio is given by equation (11). Let S(x) be a projective transformation:
where . Then
Therefore [S(A) S(B) S(C) S(D)] = [A B C D], Q.E.D.