This construction copies a line segment to a target point **T**. The construction is based on Book I, prop 2.

## The constructionEdit

- Let
**A**be one of the end points of . Note that we are just giving it a name here. (We could replace**A**with the other end point**B**).

- Draw a line segment

- Construct an equilateral triangle (a triangle that has as one of its sides).

- Draw the circle , whose center is
**A**and radius is .

- Draw a line segment starting from
**D**going through**A**until it intersects and let the intersection point be**E**. Get segments and .

- Draw the circle , whose center is
**D**and radius is .

- Draw a line segment starting from
**D**going through**T**until it intersects and let the intersection point be**F**. Get segments and .

## ClaimEdit

## ProofEdit

- Segments and are both from the center of to its circumference. Therefore they equal to the circle radius and to each other.

- Segments and are both from the center of to its circumference. Therefore they equal to the circle radius and to each other.

- equals to the sum of its parts and .

- equals to the sum of its parts and .

- The segment is equal to since they are the sides of the equilateral triangle .

- Since the sum of segments is equal and two of the summands are equal so are the two other summands and .

- Therefore equals .