1.Rf4! Kg3
1... Kxh1 leads to 2. Kf2 Kh2 3.Rh4#
2.00! Kh3
3.R1f3#

The alternative solution is:
1.Rhg1+ Kh3
1... Kh2 leads to 2. Rg5 (2.Rg6, 2.Rg7 or 2.g8 are also possible) Kh3 3. Rh1# (after 2... Kh3 3. Rh5, 3. Rh6, 3. Rh7 or 3. Rh8 are mates respectively)
2. Rf2! Kh4
3.Rh2#
