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Algebra/Arithmetic/Root Problems
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Algebra
|
Arithmetic
Return to Roots
Arithmetic Roots Problems
Go to Order of Operations
1
25
(
1
2
)
=
25
=
{\displaystyle 25^{\left({\frac {1}{2}}\right)}={\sqrt {25}}=}
2
27
(
1
3
)
=
27
3
=
{\displaystyle 27^{\left({\frac {1}{3}}\right)}={\sqrt[{3}]{27}}=}
3
(
648
+
648
)
1
4
+
8
=
648
+
648
4
+
8
=
{\displaystyle (648+648)^{\frac {1}{4}}+8={\sqrt[{4}]{648+648}}+8=}
4
512
2
3
=
(
512
3
)
2
=
{\displaystyle 512^{\frac {2}{3}}=({\sqrt[{3}]{512}})^{2}=}