# A-level Mathematics/OCR/M1/Force as a mk Vector

< A-level Mathematics‎ | OCR‎ | M1

## Vectors

A vector is a quantity that has both a magnitude (or a size) and a direction. The opposite of vectors are scalars. Scalars only have a magnitude. There is no direction. For example, speed is a scalar as speed is the same regardless of direction. This is best illustrated as a triangle:

Our point, P, is a plane travelling along the hypotenuse of this triangle at a speed of $5ms^{-1}$ . Its velocity, however, is not 5. As velocity is a vector and has both magnitude and direction, the speed of P is equal to moving at a velocity of $4ms^{-1}$  along the horizontal and $3ms^{-1}$  along the vertical.

There are several different ways of writing this as a vector. One of the most common is the i and j notation. Where i is the horizontal component of the velocity and j is the vertical component of the velocity. Using this notation, our plane would have a velocity of (4i + 3j)

Another common way of writing vectors is in the form of ${x \choose y}$  where x is the horizontal component and y is the vertical component. Using our plane as the example, is this vector form its velocity would be ${4 \choose 3}ms^{-1}$ .

To change a Vector into its horizontal and vertical components we:

1. Draw a triangle representing the vector.

2. Label all known values on triangle.

3. Use trigonometry to solve.

E.g. A force, P, with magnitude 25N has a direction of $arcsin$  ${\frac {7}{25}}$  (arcsin is the opposite of $sin$ .), find the horizontal and vertical components of P

Triangle

Label triangle:

Use trigonometry: is $\arcsin \theta$  is ${\frac {7}{25}}$  then $\theta$  is $sin$  ${\frac {7}{25}}$ . Sin is O/H. Therefore the vertical component of P is 7. The Horizontal component can be found by using Pythagoras' theorem or recognising 7, 24, 25 as a Pythagorean triple. Pythagoras' theorem says that $a^{2}$ +$b^{2}$ =$c^{2}$  where c is the hypotenuse and a and b are the adjacent and opposite (order does not matter). Therefore $\ 25^{2}-\ 7^{2}\$  = $horizontalcomponent^{2}$  = 576. $576^{\frac {1}{2}}$  = 24. In i and js this is (24i+7j).