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0.999.../Proof by equivalence of Cauchy sequences
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0.999...
Assumptions
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Construction of the real numbers from Cauchy sequences
Definition from Cauchy sequences
The limit of a geometric sequence
Proof
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In this formalism the task is to show that the sequence of rational numbers
(
1
−
0
,
1
−
9
10
,
1
−
99
100
,
…
)
=
(
1
,
1
10
,
1
100
,
…
)
{\displaystyle \left(1-0,1-{9 \over 10},1-{99 \over 100},\dots \right)=\left(1,{1 \over 10},{1 \over 100},\dots \right)}
has the limit 0.