Trigonometry/Circles and Triangles/The Simson line

Take any triangle ABC and any point P on its circumcircle. Let the perpendiculars from P to AB, BC and CA be D, E and F respectively. (At least one side will need to be produced to meet the perpendicular.) Then D, E and F all lie on a straight line, the Simson line of that point.

This theorem is due to Robert Simson, 1687-1768.

Last modified on 28 May 2011, at 17:26