- Definition 1 (Topological Manifold)

A topological space is called an *-dimensional topological manifold* (or *-manifold*) if,

- is Hausdorff.
- is second-countable.
- Every point
*has an open neighbourhood that is homeomorphic to an open subset of .*

Note: As a convention, the ball is a single point. Any space with the discrete topology is a 0-dimensional manifold.

Note also that all topological manifolds are clearly locally connected.

To emphasize that a given manifold is -dimensional, we will use the shorthand . This is not to be confused with an -ary cartesian product . However, we will prove later that such a construction *does* exist as well.

The alert reader may wonder why we require the manifold to be Hausdorff and second-countable. The reason for this is to exclude some pathological examples. Two such examples are the *long line*, which is not second-countable, and the *line with two origins*, which is not Hausdorff.

- Theorem 2

A topological manifold is connected if and only if it is pathwise connected.

*Proof*: Since all topological manifolds are clearly locally connected, the theorem immediately follows. ∎

- Definition 3

Let be a topological -manifold. Let and be an open neighborhood of . Now, let , where , be a homeomorphism. Then the pair is called a *chart at *.

- Definition 4

Let be a topological -manifold, and let be charts on such that . That is, is an open covering of . Then is called an *atlas* on .

- Definition 5

Let be an -manifold and let and be charts are a point (so ). Define the *transition function* (or *chart transformation*) between the two charts as the homeomorphism .

Given a pair , where is an -manifold and is an atlas on , properties that may satifsy are often expressed as properties of the transition functions between charts in . This is how we will define our notion of a *differentiable manifold*.

- Definition 6

An atlas for a manifold is *smooth* (or ) if all the transition functions are smooth (All higher order partial derivatives exist and are continuous).

- Definition 7

A *diffeomorphism* is a smooth homeomorphism such that is also smooth.

Note that in a smooth atlas, all transition functions are diffeomorphisms.

- Definition 8

Let be a manifold and be a smooth atlas on . Then, define as the set of all charts on such that for all , and are smooth.

A chart with the property described above is said to be *compatible* with .

- Lemma 9

is a smooth atlas on .

*Proof*: We have to show that the transition functions between any pair of charts in are smooth. This is obvious if one of then is in, so let and be charts in that are not in , such that . Let be a chart such that . Then and are both smooth, since, both and are compatible with . Then, is smooth since it is a composition of smooth maps. An identical argument for completes the proof. ∎

It should be obvious that if is a smooth atlas containing a smooth atlas , then .

## Smooth mapsEdit

- Definition 10

Let be smooth manifolds, , and let be a function. Then, if for any charts on and on such that and , the function from to is a smooth function on euclidean spaces, then is said to be *smooth at* . is called a *smooth function* if it is smooth for all .

- Lemma 11

is smooth at if and only if there exists charts on and on with such that is smooth.

*Proof*: is continuous since is smooth and thus continuous and and are homeomorphisms. Let and be two other charts at and . Then which is a composition of smooth functions since the atlases on and are smooth, and is therefore smooth. ∎

- Remark 12

By Lemma 11, we do not have to check *all* charts to see if a function is smooth. A relief, since maximal atlases tend to be uncountably big.

- Definition 12

If is a smooth bijective function such that its inverse is smooth too, it is called a *diffeomorphism*. Two manifolds are called *diffeomorphic* if there exists a diffeomeorphism between them.

- Lemma 13

Let and be smooth. Then is smooth as well.

*Proof*: Let , and be charts on at respectively. Then which is a composition of smooth maps of euclidean space and is hence smooth. ∎