Solutions To Mathematics Textbooks/Basic Mathematics/Chapter 2

Chapter 2

Section 1

11

$ax + by = u\,$

$cx + dy = v\,$

$acx + bcy = uc\,$

$acx + ady = va\,$

$(acx + bcy)-(acx + ady) = uc - va\,$

$bcy - ady = uc - va\,$

$y(bc - ad) = uc - va\,$

$y = \frac{uc-va}{bc-ad}$

Last modified on 22 November 2011, at 13:52