Solutions To Mathematics Textbooks/Algebra (9780817636777)/Exercises 26-50

Exercise 42Edit

aEdit

If a and b had a nontrivial common factor k >= 2, then a = k*a' and b = k*b', so (ad - bc) = k(a'd - b'c) = ±1.

Alternatively, you must essentially show that a and b are coprime; that is the numerator and denominator share no common factor. Another way of saying this is to say that gcd(a, b) = 1.

Let g = gcd(a, b). We can write ad-bc = \pm 1 as \left(\frac{a}{g} \cdot gd - \frac{b}{g} \cdot gc\right) = g \left(\frac{a}{g}d - \frac{b}{g}c \right) = \pm 1. Thus g must be either -1 or 1, and thus a and b are coprime.

Last modified on 14 June 2012, at 22:41