# Ordinary Differential Equations/Without x or y

## Equations without yEdit

Consider a differential equation of the form

F(x, y')=0.

If we can solve for y', then we can simply integrate the equation to get the a solution in the form y=f(x). However, sometimes it may be easier to solve for x. In that case, we get

$x=f(y')$

Then differentiating by y,

${1 \over y'}={df \over dy'}{dy' \over dy}$

Which makes it become

$y=C+\int y' {df \over dy'} dy'$.

The two equations

$x=f(y')$

and

$y=C+\int y' {df \over dy'} dy'$

is a parametric solution in terms of y'. To obtain an explicit solution, we eliminate y' between the two equations.

If it is possible to express

F(x, y')=0

parametrically as x=f(t), y'=g(t),

then one can differentiate the first equation:

$\frac{1}{y'}\frac{dy}{dt}=f'(t)$

So that

$y=C+\int g(t)f'(t)dt$

to obtain a parametric solution in terms of t. If it is possible to eliminate t, then one can obtain an integral solution.

## Equations without xEdit

Similarly, if the equation

F(y, y')=0.

can be solved for y, write y=f(y'). Then the following solution, which can be obtained by the same process as above is the parametric solution:

y=f(y')

$x=C+\int \frac{f'(y')}{y'} dy'$

In addition, if one can express y and y' parametrically

y=f(t), y'=g(t),

then the parametric solution is

y=f(t),

$x=C+\int \frac {f'(t)}{g(t)} dt$

so that if the parameter t can be eliminated, then one can obtain an integral solution.