Computer Programming/Physics/Position of an accelerating body function

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      The position of an accelerating body can be described by a mathematical function \mathbf{s}(t). The generalized function can be attained by using the Taylor series

      \mathbf{s}(t+t_0)=\sum\frac{t^n}{n!}\mathbf{s}^{(n)}(t_0),

      where \mathbf{s}^{(n)} is the nth derivative of \mathbf{s}:

      • \mathbf{s}^{(0)}=\frac{d^0\mathbf{s}}{dt^0}=\mathbf{s}
      • \mathbf{s}^{(1)}=\frac{d^1\mathbf{s}}{dt^1}=\mathbf{v}
      • \mathbf{s}^{(2)}=\frac{d^2\mathbf{s}}{dt^2}=\mathbf{a}
      • etc.

      The accuracy of this function depends on the number of terms used as \frac{1}{n!} decreases rapidly. Additionally, the time t can be synchronized such that t_0=0 (Maclaurin series).

      Note that for a constant acceleration most of the terms become zero and we're left with

      s(t)=\frac{1}{0!}\mathbf{s}_0+\frac{t}{1!}\mathbf{s}^{(1)}_0+\frac{t^2}{2!}\mathbf{s}^{(2)}_0

      or

      \mathbf{s}(t)=\mathbf{s}_0+\mathbf{v}_0t+\frac{1}{2}\mathbf{a}t^2

      C++

      template<class Vector,class Number>
      Vector PositionAcceleratingBody(Vector *s0,Number t,size_t Accuracy)
      {
           Vector s(0);     //set to zero if int, float, etc. or invoke the
                            //     "set to zero" constructor for a class
           Number factor(1);//0!==1 and t^0==1
           for(size_t n(0);n<Accuracy;n++)
           {
                if(n)factor*=(t/n);//0!==1 and t^0==1
                s+=(factor*s0[n]); //s0 is the array of nth derivatives of s
                                   //     at t=t0=0
           }
           return s;
      }
      
      

      Justification for Using the Taylor Series

      The Taylor series can be derived by systematically selecting which of our variables is a constant and then extrapolating that to the infinite limit.

      • Constant Position
      s(t)=s_0
      or
      s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)
      • Constant Velocity
      v(t)=v_0
      s(t)=\int vdt=\int v_0dt
      s(t)=v_0t+s_0
      or
      s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)+\frac{t^1}{1!}s^{(1)}(t_0=0)
      • Constant Acceleration
      a(t)=a_0
      v(t)=\int adt=\int a_0dt
      v(t)=a_0t+v_0
      s(t)=\int vdt=\int (a_0t+v_0)dt
      s(t)=\frac{1}{2}a_0t^2+v_0t+s_0
      or
      s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)+\frac{t^1}{1!}s^{(1)}(t_0=0)+\frac{t^2}{2!}s^{(2)}(t_0=0)
      • Constant Rate of Change of Acceleration
      a^{(1)}(t)=a^{(1)}_0
      a(t)=\int a^{(1)}dt=\int a^{(1)}_0dt
      a(t)=a^{(1)}_0t+a_0
      v(t)=\int adt=\int (a^{(1)}_0t+a_0)dt
      v(t)=\frac{1}{2}a^{(1)}_0t^2+a_0t+v_0
      s(t)=\int vdt=\int (\frac{1}{2}a^{(1)}_0t^2+a_0t+v_0)dt
      s(t)=\frac{1}{6}a^{(1)}_0t^3+\frac{1}{2}a_0t^2+v_0t+s_0
      or
      s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)+\frac{t^1}{1!}s^{(1)}(t_0=0)+\frac{t^2}{2!}s^{(2)}(t_0=0)+\frac{t^3}{3!}s^{(3)}(t_0=0)
      • etc.
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      Last modified on 18 December 2008, at 01:42