# Basic Algebra/Solving Equations/Solving Equations with Variables on Both Sides of the Equation

## VocabularyEdit

Variable - a letter (A-Z) that takes the place of a number.

Equation - an example would be: 8y - 3 = 1 + 10y (The answer is -2 [negative two] = y)

## LessonEdit

NOTE: WHAT YOU DO TO ONE SIDE YOU MUST DO TO THE OTHER! NO EXCEPTIONS!

1) do the distributive property.

2) Combine like terms on both sides.

3) add/subtract numbers next to a variable on both sides.

4) divide by the number next to the variable on both sides.

5) The answer should look like: x=20 or 20=x

(Note: the variables and numbers may vary in your answer.)

## Example ProblemsEdit

A simple problem:

$2(x+5)=5(x-10)$<---Problem

$2x+10=5x-50$<---Distributive Prop.

$2x+10-2x=5x-2x-50$<---Subtract the variables with numbers next to them.

$10=3x-50$<---This is what you're left with.

$10+50=3x-50+50$<---get rid of the 50 by subtracting

$60=3x$<---This is what you're left with.

$60/3=3x/3$<---Get rid of the three by dividing by three

$20=x$<---This is your answer.

## Practice GamesEdit

Put links here to games that reinforce these skills

Purplemath.com: http://www.purplemath.com/modules/index.htm

## Practice ProblemsEdit

(Note: put answer in parentheses after each problem you write)

Practice Problem #1:

3v - 2 = v + 16

{v = 9}

Practice Problem #2:

2x = 15 - x

{x = 5}

Practice Problem #3:

([z - 5] / -3) = 9 + 3.4z

{z = -1.96}

Last modified on 19 July 2010, at 15:53